(25x^-3y^20)/(35x^5y^4)

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Solution for (25x^-3y^20)/(35x^5y^4) equation: 


D( x )

x = 0

35*x^5*y^4 = 0

x = 0

x = 0

35*x^5*y^4 = 0

35*x^5*y^4 = 0

35*x^5*y^4 = 0 // : 35*y^4

x^5 = 0

x = 0

x in (-oo:0) U (0:+oo)

(25*x^-3*y^20)/(35*x^5*y^4) = 0

5/7*x^-8*y^16 = 0 // : 5/7*y^16

x^-8 = 0

x naleu017Cy do O

x belongs to the empty set

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